x^2-34x+120=0
i need to find out the value for x
2006-11-14 19:28:28 · 9 answers · asked by Kenny 1 in Science & Mathematics ➔ Mathematics
x^2 -30x-4x+120 = 0
x(x-30)-4(x-30)=0
(x-4)(x-30)=0
x=30 or 4
2006-11-14 19:32:29 · answer #1 · answered by yog 2 · 1⤊ 1⤋
The value of x will be -43 ( negative number)
-43 x 2 -34 + 120=0
-86 - 34 +120 = 0
-120 +120 =0
0=0
got it ?????
2006-11-14 19:39:04 · answer #2 · answered by bks 2 · 0⤊ 0⤋
x^2-34x+120=0
(x-30)(x-4)=0
x-30=0 or x-4=0
x=30,4
This kind of equation can be factorized using the normal method. If it can't be factorized, you will have to solve it using the formula you have learnt in school.
2006-11-14 20:02:57 · answer #3 · answered by Anonymous · 0⤊ 0⤋
for an equation in the form of:
aX^2+bX+c=0
The solution is:
(-b+/-sqrt(b^2-4ac))/(2a)
so
(34+/-sqrt(676))/2 or 30 and 4
check 30^2 -34*30 + 120 = 0 yep
check 4^2-34*2+120=0 yep
x is 30 or 4
2006-11-14 19:39:24 · answer #4 · answered by Anonymous · 0⤊ 0⤋
x^2-34x+120=0
=>x^2-34x+120=0
=>x^2-30x-4x+(30*4)=0
=>x(x-30)-4(x-30)=0
=>(x-30)(x-4)=0
=>(x-30)=0 or (x-4)=0
=>x=30 or x=4
All the best.
2006-11-14 20:03:01 · answer #5 · answered by Paritosh Vasava 3 · 0⤊ 0⤋
x² - 34x + 120
(x - 30)(x - 4)
- - - - - - - - - -
x = 30
0r
x = 4
- - - - - - - s-
2006-11-15 00:13:13 · answer #6 · answered by SAMUEL D 7 · 0⤊ 0⤋
(x-30)(x-4)=0
2006-11-14 19:33:08 · answer #7 · answered by igot4onit 2 · 0⤊ 1⤋
sum=-34 and product=120
the factors are(x-4)(x-30)=0
so x=30 or 4
2006-11-14 19:33:41 · answer #8 · answered by raj 7 · 0⤊ 1⤋
hhahahhaa,,no.
2006-11-14 19:32:16 · answer #9 · answered by Anonymous · 1⤊ 2⤋