2+2=5....Prove it??

Answer 1

2.3 + 2.3 = 4.6

2.3 rounds down to 2
2.3 rounds down to 2 again
4.6 rounds up to 5
therefore 2+2=5

Answer 2

2+2=4

Answer 3

quite simple 2 is an equivalent of everything. without 1 you can not have 2 without bad there is no good without happy there is no sad. A paradox literally. So really double of anything equals 1 item because the 2 cancel each other out so you are left with 0 until combination is complete. upon the 2 losing its place it cannot become 1 without a co-existent opposite. so now you are back to 2 and the process repeats. as long as you have an even you will always have an odd. example: 2 + 2 drops to 1+1 = 2 = 1 see the process equals a 5-point equation expressed by opposing the first question thus proving the equation is correct. I know it may seem a little difficult to understand at first but read it a few times and you will catch on.

Answer 4

If 4+4=10

Answer 5

2 + 2 = 4

Answer 6

in physics numbers r not constant as 1 singularity. therefore 2 is not always 2, but can be 3 and 2 at the same time, so 2+3=5.

but this leaves the question if at this point that maybe the 2's r valued at 2 and the 5 is valued at 4.

Answer 7

1+1=2 therefore 1+1+1+1=4 1+1+1+1+1=5 2^2=4;2+2=4;2+2+1=2^2+1;16=8*2=10*2;2^4=2^2*5there fore from this 2+2=5 here i used that 2+2=5is there but i multiplied both sides by 2 and i got the result 8=10 by that i solved 8*2=10*2 ;and i made2^3*2=2^4and 2*5*2=2^2*5and i equated the both equations like 2^4/2^2=5;2^2=5 as per the above discussion 2^2=4which is =2+2; by this way i proved 2+2=5

Answer 8

Let 2=2.
Let the other 2=3
Then 2+2=2+3=5
Therefore 2+2=5
(I do not know if this is mathematically accurate but as far as I can see there are no mistakes. I have a 100,000$ reward for anyone who finds a mistake. The reward will probably go up to 200,000$ if no one answers it in a few months.)

Answer 9

Yes i can prove it and can tell you where i am wron too
-20=-20
16-36 = 25 - 45
4^2 - 2*4*9/2 = 5^2 - 2*5*9/2
4^2 - 2*4*(9/2) + (9/2)^2 = 5^2 - 2*5*(9/2)+ (9/2)^2
(4-9/2)^2 = (5-9/2)^2
Taking suare root on both sides ( it is where i am wrong)
4-9/2 = 5- 9/2
4 = 5 ( adding 9/2 on both the sides)
2+2 = 5
Where i am wrong here is while taking squre root on both the sides, what we have to do is to use a plus/ minus sign in those places and after taking squre root operation the value will be correct only for one of these signs not with both; ohterwise what would happen?::
(1)^2 = (-1)^2 ( because value for both equals 1)
taking squre roor
1= -1
Adding 4
4+1 = 4-1
5 = 3
and many more.........................................

Answer 10

Let 2 be a large value of 2 so that it is accompanied by a perturbation from the constant by a value epsilon. The 2 + 2 = 4+ (2*epsilon) = 5 whenever you let epsilon = .5

Therefore whenever 2 is allowed to possibly be pertubed by .5 it is possibly for 2+2 = 5.

Answer 11

2+2

(2+2)/2

(2+2)/2+1

{(2+2)/2+1} * 2

[ {(2+2)/2+1} * 2 ]-1 = 5