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Can any help me with a step-by-step explanation on how this problem comes out to the answer.

Problem: 8x + 7y - (2x - 6y)
(Distribute the -1 to 2x and 6y)

Answer: 6x + 13y

Help appreciated; TQ.

2006-11-14 15:25:00 · 9 answers · asked by Noel 1 in Science & Mathematics Mathematics

9 answers

8x + 7y - (2x - 6y)
Step 1: 8x + 7y - (2x) -(-6y)
Step 2: 8x + 7y - 2x + 6y
Step 3: (8x - 2x) + (7y + 6y)
Step 4: (6x) + (13y)
Step 5: 6x + 13y
1. First, we use the Distributive property. The negative sign in front of the (2x - 6y) implies that it is multiplying everything within the parentheses by -1.
2. Now we have to fix the signs. Remember: -1 x -1 is positive 1. Thus -(-6y) = 6y.
3. Now we put the similar terms together.
4. Now we add and subtract whats inside the parentheses.
5. Done!

Hope I helped. =)

2006-11-14 15:41:12 · answer #1 · answered by taceflacce 2 · 0 0

If you distribute the -1 that means the - in front of the (). So change that - to a + and put a - in front of the terms in the ()

8x + 7y + (-2x - -6y)

Since two negatives make a positive you get

8x + 7y +(-2x + 6y)

since you have a + in front of the () you can get rid of the ()

8x + 7y + -2x + 6y

combine like terms (you can't mix x and y in addition or subtraction) 8x - 2x is 6x and 7y + 6y is 13y so you have a final answer of

6x + 13y and you can't simplify it any further than that

2006-11-14 15:33:12 · answer #2 · answered by Freya 2 · 0 0

After distributing the -1, your problem becomes:

8x + 7y - 2x + 6y

To simplify combine like terms ( x's with x's, y's with y's);

(8x - 2x) + (7y + 6y) = 6x + 13y

2006-11-14 15:30:28 · answer #3 · answered by chava 2 · 0 0

first, distribute the (-1) to the 2x and 6y

==> 8x +7y - 2x + 6y

combine like terms

==> 8x - 2x + 7x +6x

add them up

==> 6x + 13y

2006-11-14 15:28:12 · answer #4 · answered by jacobrcotton 3 · 0 0

let us divide the equation into two parts
part 1: 8x+7y
Part 2: -(2x-6y)

first let us solve part two

multiply the euation by -(Minus), because minus is in the front

Now it becomes -2x -(-6y)
-2x+6y

now add Part 1 + Part2


8x+7y+(-2x+6y)

which is same as


8x+7y-2x+6y


now performing the addition


8x-2x+7y+6y


which equals


6x+13y

2006-11-14 15:37:05 · answer #5 · answered by Kewl guy 3 · 0 0

8x + 7y - (2x - 6y)
= 8x +7y - 2x + 6y (subtracting a negative number -6y would give a positive)
= 8x- 2x + 7y + 6y (add or subtract the x's and y's)
= 6x + 13y

2006-11-14 15:29:50 · answer #6 · answered by good_thinking_robin 2 · 0 0

How about I help you with the first one? Its pretty simple. First and foremost, you have to understand this stuff is hard. Secondly, you must memorize all the identities they taught you at school, such as double angle identities and pythagoras identities and the like. A helpful hint is to convert everything to sin and cos before you procede. Thus, for the number 1 cos θ ( 1/cosθ - cosθ) = (sinθ)^2 note that secθ = 1/cosθ- memorize that and multiply cos θ in! so 1 -(cosθ)^2 = (sinθ)^2 note the secθ and cosθ cancel each other out now note that since (sinθ)^2 + (cosθ)^2 = 1, 1-(cosθ)^2 = (sinθ)^2 substitue that into the left side of the equation so (sinθ)^2 = (sinθ)^2 Job done! So first step is to memorize those identities, second is to make everything sin and cos, and last is to plug those identities and solve. If you need more help, just ask.

2016-03-28 06:04:05 · answer #7 · answered by Anonymous · 0 0

=8x+7y-2x+6y -*-=+ +*-=-
=6x+13y

2006-11-14 15:45:35 · answer #8 · answered by J.Bo 2 · 0 0

You add the like terms

2006-11-14 15:28:00 · answer #9 · answered by MateoFalcone 4 · 0 0

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