can someone please walk me thru the process
log4(1/64)
how do i go about solving that
2006-11-14 14:46:47 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
=log 4^(-3) to the base 4
=-3 log 4 to the baseb4
=-3
2006-11-14 15:06:15 · answer #1 · answered by raj 7 · 0⤊ 0⤋
since you have a log4 or log with base 4, you must think about 4 to what number is 1/64
4^3 is 64. To get the reciprocal, you'd need 4^-3
so log4 (1/64) = -3
2006-11-14 22:50:02 · answer #2 · answered by J G 4 · 0⤊ 0⤋
Remember that logb(x)=y is the same as b^y=x
4^x=1/64
Solve for X
x ln 4= ln(1/64) Plug it in a calculator!
x=(ln(1/64))/ln4
x=-3
2006-11-14 22:52:59 · answer #3 · answered by venom90011@sbcglobal.net 1 · 0⤊ 0⤋
log(4)(1/64) = log(4)(1/(4^3)) = log(4)(4^(-3)) = -3log(4)4 = -3
2006-11-14 23:33:22 · answer #4 · answered by Sherman81 6 · 0⤊ 0⤋