Can anyone help me completely factor this expression?
Thanks!
a^2(b-c)-b^2(a+c)+c^2(b-a)+3abc
2006-11-14 14:46:11 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
a^2(b-c)-b^2(a+c)+
c^2(b-a)+3abc
2006-11-14 14:53:38 · update #1
Yes, this is my question.
(a^2b-a^2c)-(b^2c- b^2c)+
(c^2b-c^2a)+3abc
Sorry for any confusion
2006-11-14 15:07:52 · update #2
(a^2b-a^2c)-(b^2a- b^2c)+(c^2b-c^2a)+3abc
2006-11-14 15:16:41 · update #3
(a^2b-a^2c)-(b^2c- b^2c)+(c^2b-c^2a)+3abc
i think this is what you mean
ya i think there might be a typo
2006-11-14 14:58:29 · answer #1 · answered by Mike P 3 · 0⤊ 0⤋
They cut off your question
2006-11-14 22:50:18 · answer #2 · answered by hayharbr 7 · 0⤊ 0⤋
if you go to www.quickmath.com, click on Factor to the top left of the screen, it will factor it for you.
2006-11-14 23:35:10 · answer #3 · answered by Sherman81 6 · 0⤊ 0⤋
this looks like a cyclic expression but for the middle term.is it possible that there is a typo?will you please check?
2006-11-14 22:56:44 · answer #4 · answered by raj 7 · 0⤊ 0⤋