A baseball (m = 149 g) approaches a bat horizontally at a speed of 43.7 m/s (98 mi/h) and is hit straight back at a speed of 48.3 m/s (108 mi/h). If the ball is in contact with the bat for a time of 1.10 ms, what is the average force exerted on the ball by the bat? Neglect the weight of the ball, since it is so much less than the force of the bat. Choose the direction of the incoming ball as the positive direction.
I've used (Sum of forces)(time)=(mass x Vf) - (mass x Vo)
doesn't seem to be working, and time is in miliseconds. any help?
2006-11-14 14:11:52 · 1 answers · asked by Any help? 1 in Science & Mathematics ➔ Physics
I'm not certain there is enough information provided to answer the question. However, try this. The average force per ms is the quotient obtained when one divides: the sum of the product of the mass of the ball multiplied by the incoming impact speed of the ball plus the mass of the ball multiplied by the departing speed of the ball from the bat by the duration of the impact, 1.1ms. But, since force is measured in units of mass per sq 'unit' of size, it seems more information is necessary to solve the problem.
2006-11-14 14:35:25 · answer #1 · answered by Nightstalker1967 4 · 0⤊ 0⤋