please help me with precalc!!?

Question

i missed a day of class, my teacher is making me take a test tomorrow and wouldn't give me extra help today. please help me with asymtopes of rational functions. i know how to do it but end up with the incorrect answer. and help with factoring... i'm almost ashamed to say that i'm dependent on my calculator when it comes to factoring. any help you can give would be great

Answer 1

There are three types of asymptotes: horizontal, vertical and slant.
Vertical asymptotes occur when the denominator is zero (example: y = 3/(x-1) has a v.a. at x = 1).

Horizontal asymptotes occur when the degree of the top is less than the degree of the bottom, in which case the h.a. is y = 0.

OR, when the degree of the top is equal to the degree of the bottom, in which case the h.a. is
y = (leading coefficient of top)/(leading coefficient of bottom)

(example: y = (3x+6)/(x-5) has a h.a. at y = 3/1 or y = 3)

It has a slant asymptote if the degree of the top is exactly one more than the degree of the bottom. To find its equation, divide the top by the bottom and take the quotient (disregard the remainder). Note: if there is no remainder, you should have reduced the rational expression first.

(example: y = (x^2 + 3x + 4)/(x - 5) has a s.a. at y = x + 8

I would be happy to explain more if you want, just send an IM

Answer 2

ok for asymtopes of rational functions you have to take the variable d and divide it by the number given 39. so you get 3 but then you have to get the factorial which in most cases is 1. then you multiply 39 over x over 3 over 1 so you should get 93.

and for factoring you have to divide the variable by the factorial and to find that you have to do 3x times 7 over d / 99. you should get the answer which is 83.

Answer 3

for asymptotes, there are 3 types:
1. Verticle - let the denominator = 0, then solve for x
2. Horizontal - best if you plug into your TI 83 Plus, then you can see where the horizontal lines are.
3.Oblique - when the degree on the top is one greater than the degree on the bottom.
example: y = x^3 / x^2
for oblique, you divide the bottom by the top.
example: y = (2x^2-3) / (2x-1)
---------_________
= 2x-1 ) 2x^2-ox-3

the oblique will be: x+.5 or x+ 1/2

and for factoring...you should really get the program for your calculator, FOIL and QUADFORM

it really helps

Answer 4

For informantion on asymptotes, see http://en.wikipedia.org/wiki/Asymptote