I would appreciate any helpful input on this physics problem. I am really confused on this one. Thanks for any help :)
A 10.0 kg cylinder rollls without slipping on a rough surface. At an instant when its center of gravity has a speed of 8.0 m/s.
a) Determine the translational kinetic energy of its center of gravity.
b) Determine the rotational kinetic energy about its center of gravity.
c) Determine its total kinetic energy
2006-11-14 13:12:05 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Physics
The translational kinetic energy is .5*m*v^2. You have m and v, so compute this.
The rotational kinetic energy is .5*I*w^2, where I = moment of inertia about the rotational axis, and w = angular velocity. You need to compute the moment of inertia of the solid cylinder (I assume it's solid) You can look this up at http://en.wikipedia.org/wiki/List_of_moments_of_inertia. The angular velocity is v/r.
The total kinetic energy is the sum of the two.
2006-11-14 13:36:22 · answer #1 · answered by gp4rts 7 · 0⤊ 0⤋
a)
translational KE = 1/2 * mass * velocity^2
= 1/2 * 10 * (8^2)
= 320 Joules
b)
To determine the rotational kinetic energy, you need to know the radius of the cylinder. This isn't included in your question above...
c)
total KE = translational KE + rotational KE
2006-11-14 21:45:24 · answer #2 · answered by Christopher C 2 · 0⤊ 0⤋