The alcohol in 'gasohol' burns according to the following equation:
C2H5OH(l) + 3O2(g) --> 2CO2(g) + 3H2O(l)
If the combustion reaction consumes 33.1 grams C2H5OH reacting with excess O2, how many moles of H2O are formed?
2006-11-14 12:49:37 · 4 answers · asked by nglennie_06 1 in Science & Mathematics ➔ Chemistry
2.17 moles
the ratio is 3:1, not 2:1 as the above answerer states
2006-11-14 12:56:29 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Mr of C2H5OH = 46
Moles of C2H5OH = 33.1/46 = 0.7196 (to 4 s.f.)
From chemical equation,
moles of C2H5OH used : moles of H2O produced = 1 : 3
Hence moles of water produced = 3 x 0.7196 = 2.16 (to 3 s.f.)
Hope this helps :)
2006-11-14 13:15:43 · answer #2 · answered by chyrellos 2 · 0⤊ 0⤋
33.1 g C2H5OH x (mol / 46 g) x (2 mol H2O / 1 mol) = 1.44 mol H2O
2006-11-14 12:55:14 · answer #3 · answered by scurvybc 3 · 0⤊ 1⤋
1.44 mol
2006-11-15 20:09:55 · answer #4 · answered by frankmilano610 6 · 0⤊ 0⤋