The length of a rectangle is twice its width 5 yd. If the perimeter of the rectangle is , find its area. Please Help! As fast as you can!
2006-11-14 12:35:54 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
We know that the width is 5 yards, and that the length is double that, we can deduce that the length is 5x2=10. So the rectangle is 5x10.
This means that the perimeter is 5x2+10x2=30 yards. Since there are two sides length wise, and two width wise.
The area is the length times the width, 5x10=50 square yards.
Again, if you want to grow as a person you need to solve these yourself. The time it took you to copy all these questions onto Yahoo! you should have been able to answer them yourself. If you don't know how, you should be asking your teacher to explain them and give you extra tuition.
2006-11-15 03:36:02 · answer #1 · answered by ZCT 7 · 0⤊ 0⤋
If its width is 5 yd and its length is twice that, the length is 10 yd. If the rectangle is 5 yd x 10 yd, then the perimeter is 30 yd (5 yd + 10 yd + 5 yd + 10 yd = 30 yd) and its area is 50 sq. yds (5 yd x 10 yd = 50 sq. yds)
2006-11-14 20:46:25 · answer #2 · answered by Mr. Awesome! 4 · 0⤊ 0⤋
Wow! What Luck! I've just happened upon the world's first rectangle emergency!
2006-11-14 20:44:28 · answer #3 · answered by worldinspector 5 · 0⤊ 0⤋
Area=125 i think good luck
2006-11-14 20:43:45 · answer #4 · answered by Rebecka lovebug 2 · 0⤊ 0⤋
I probably know the answer or the soltion but it's really hard to teach to on the internet
2006-11-14 20:37:52 · answer #5 · answered by Anonymous · 0⤊ 0⤋
Take better notes in class
2006-11-14 20:37:36 · answer #6 · answered by Anonymous · 0⤊ 0⤋
Please retype the question; you have left out some things.
2006-11-14 20:38:21 · answer #7 · answered by hayharbr 7 · 0⤊ 0⤋