No because 2+ 4 = 6 < 8
sum of 2sides must be greater than 3rd side
2006-11-14 12:24:48
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answer #1
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answered by Mein Hoon Na 7
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Here's another way of looking at this. Since the longest side is 8, it must be the base of the triangle, because, by convention, this is the way triangles are usually represented. Now suppose the other two sides are 2 and 4 respectively. We allow those two sides to collapse onto the base. If they are long enough to form an angle opposite the longest side, then their sum must be longer than the length of the base. If they aren't, there is no way they can meet to form an angle. If the sum of their lengths is equal to the base, they collapse on it to form a straight line, which as we all know, is not a triangle. Since these lengths are 2 and 4, their sum is less than 8, so the various sides cannot form a triangle.
2006-11-14 12:44:59
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answer #2
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answered by MathBioMajor 7
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No. For the sides of any triangle; a, b, and c the following must be true.
a + b > c
a + c > b
b + c > a
Since, 4 + 2 is NOT greater than 8, this can not be a triangle.
2006-11-14 12:26:13
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answer #3
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answered by Anonymous
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no. a 4 sided polygon is a rectangle, there's no such thing as a 2 sided polygon(you can't make a defined area with only 2 lines) and an 8 sided polygon is an octagon. I guess it just depends on the definition of triangle. Tri=3
2006-11-14 12:30:45
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answer #4
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answered by darcy_t2e 3
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No - the two shorter sides of a triangle must be greater than the longest side.
addendum; who's the guy giving all these people with correct answers the thumbs down?
2006-11-14 12:30:16
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answer #5
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answered by Anonymous
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maybe the Bermuda triangle TRI means 3
2006-11-14 12:27:57
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answer #6
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answered by kissybertha 6
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Try drawing it yourself: Draw an 8cm line, then see if you can draw 4cm from one end and 2cm from the other to make a triangle. Once you've tried that you won't need anyone else to tell you the answer.
2006-11-14 12:25:31
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answer #7
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answered by Hy 7
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