What is the slop of a line parallel to 2x+4y=-17? express your answer as a common fraction
2006-11-14 12:14:55 · 5 answers · asked by firedragonof2005 1 in Education & Reference ➔ Homework Help
First you have to put the equation in slope-intercept form.
2x + 4y = -17
-2x -2x
4y = -2x -17
/4 /4
y = -1/2x -17/4
Slope-Intercept form:
y = mx + b
m= slope
b= y-intercept
So,
m = -1/2
2006-11-14 12:19:54 · answer #1 · answered by lightsaber_tech 2 · 0⤊ 0⤋
The slope is -1/2. The y intercept can be anything except -17/4. The formal way of writing this would be "y=-x/2 + [not -17/4].
2006-11-14 20:28:44 · answer #2 · answered by robertspraguejr 4 · 0⤊ 0⤋
2x+4y=-17
subtract 2x
4y = -2x - 17
divide by 4
y = -2/4x - 17/4
then simplify the fractions
the one with the x is your slope
2006-11-14 20:17:28 · answer #3 · answered by Ambino 4 · 0⤊ 0⤋
y=(-1/2)x -(17/4) so your slope would be the same which is negative 1/2
2006-11-14 20:18:52 · answer #4 · answered by angel_babydoll_devil08 2 · 0⤊ 0⤋
2
the number in front of x is the slope y=mx+b
2006-11-14 20:16:38 · answer #5 · answered by motor mouth 2 · 0⤊ 1⤋