2006-11-14 12:02:07 · 4 answers · asked by chelsea y 1 in Science & Mathematics ➔ Mathematics
10(x-2)(x-1)/(x-1)(x+1) you get this by factoring. The factor (x-1) is common to the numerator and denominator so it cancels out leaving you with (10x-20)/(x+1)
2006-11-14 12:09:30 · answer #1 · answered by MollyMAM 6 · 0⤊ 0⤋
10x² - 30 x + 20 = 10(x² - 3x + 2) = 10(x - 2)(x - 1)
x² - 1 = (x + 1)(x - 1)
You can cancel out the (x - 1) on top and bottom, leaving you with:
10(x - 2)/(x + 1)
2006-11-14 12:08:09 · answer #2 · answered by Dave 6 · 0⤊ 0⤋
Focusing on the numerator first:
Factor out that 10 so you can see the real problem:
10(x^2 - 3x + 2) = 10(x -2)(x-1), using the rule of what two numbers whose product is 2 and whose sum is -3.
The denominator: (x^2 - 1) = (x + 1)(x-1), what two numbers whose product is -1 and whose sum is zero.
Putting it together:
10(x - 2)(x - 1)/[(x + 1)(x - 1)], the (x - 1)'s cancel,
Answer:
10(x - 2)/(x + 1)
2006-11-14 12:08:51 · answer #3 · answered by Action 4 · 0⤊ 0⤋
10x-20/x-1
2006-11-14 12:05:24 · answer #4 · answered by L 4 · 0⤊ 1⤋