i need help?

Question

the allele for a cleft chin, C, is dominant among humans. what are the results of a cross between parents with genotypesCc and cc?

Answer 1

Find the gametes of each parent. Let's say dad is Cc, then half the spermatozoids will be C and half will be c. For mom, if she's cc, then all the eggs will be c. This means that a baby would have 50% chance of being Cc and 50% chance of being cc.

Answer 2

...C.c
c.C.c
c.C.c

BUT this depends upon Male and female. If the dominant Cc is Dad and the recessive cc is Mom

XY & XX
Cc & cc

if they produce a son,
Y&X -> 100% cc (Y in male always recessive gene)
daughter
X&X -> 100% Cc (because X in male is always dominant gene)

Mother has dominant Cc, Father has cc
son 50% Cc (depends upon which of Mom's X's mixes with Dad's Y)
daughter 50% Cc (same reason)

Problem comes into this because now we have a large percentage of XXX, XYX, XYY, mutations -> because of all the pesticides and hormones and chemicals in our environment.

We might have to change the way we do our gene tables...

Answer 3

Just do a simple Punnant's square:

C | c
c| Cc| cc
_________
c| Cc| cc

So 50% Cc and 50% cc

The male/female doesn't apply in this situation as it doesn't state that this is a sex related gene, so it doesn't matter if it's an X or Y gene, it's most likely on another chromosome :)

Answer 4

Cc cc
Cc cc

Answer 5

well do the mating ritual dance:

one from Cc mates with one from cc, so we get:

Cc, Cc
cc, cc

so you get half Cc and half cc