Do u know how to doy=x^2-5x+4 so i can graph it also y=1/2x^2?

Question

I need to have an x and y value for both of them and i know how to do it but it is not comming out right for me now.

Answer 1

y=1/2x^2 is a "happy" curve with turning point at (0,0)

y=x^2-5x+4 can be written as:
y=(x-5/2)^2 - 9/4

This is a "happy" curve with turning point at (-5/2, -9/4)

Answer 2

Check your answers

Plot y=x^2-5x+4
x y
-2 18
-1 10
0 4
1 1
2 -2
Plot y=1/2x^2
x y
-2 1/8
-1 1/2
0 infinity
1 1/2
2 1/8

Answer 3

Yes I do but im not dooin your homework look in your notes, or if you were like me and didnt take any look in the book