What type of curve should this be ? Any guesses ? where shoud i look for the answer ?
2006-11-14 09:56:18 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
z = 6 is a plane parallel to the x-y plane through 6 on the z-axis
(x+2)² + (y-2)² = 2² is a cylinder with axis through (-2, 2) on the x-y plane parallel to the z-axis with a radius of 2
So what you have described is a circular cross-section of that cylinder cut off by the plane z = 6
Parametrically x = -2 + 2cosθ, y = 2 + 2sinθ, z = 6
Reasons:
x = -2 + 2cosθ →x+2 = 2cosθ, so (x + 2)² = 2²cos²θ
y = 2 + 2sinθ → y - 2 = 2sinθ, so (y - 2)² = 2²sin²θ
Whence (x + 2)² + (y - 2)² = 2²(cos²θ + sin²θ) = 2²
And z = 6 is not variable
2006-11-14 10:15:15 · answer #1 · answered by Wal C 6 · 0⤊ 0⤋
it's a circle x^2+y^2+4x-4y+8=4
hope i was helpful
2006-11-14 10:07:15 · answer #2 · answered by Matteo R 3 · 0⤊ 0⤋
Hey, do your own homework! Translation: I haven't a clue what you are talking about.
2006-11-14 10:03:42 · answer #3 · answered by Ceci 4 · 0⤊ 0⤋
^ above me is insane lol
2006-11-14 10:20:35 · answer #4 · answered by Anonymous · 0⤊ 0⤋