here it is...
find an 8 digit number that meets the following criteria
the first digit tells you how many zeros are in the number
the second digit tells you how many ones are in the number
the third digit tells you how many twos are in the number
ect....
for ex: In the number 21200 there are 2 zeros so you put a 2 in the first spot
please help me i am kind of stumped
2006-11-14 09:20:07 · 8 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
42101000
2006-11-14 09:21:03 · answer #1 · answered by Anonymous · 0⤊ 3⤋
There is only one number that will work. This is assuming, of course, we are talking a straight base 10 number (no funny stuff) where each digit has to be some number between 0 and 9. You can arrive at the conclusion through deduction by just going through some thinking regarding the very first digit (signifying the # of zeros). Should I give the answer?
2006-11-14 17:48:29 · answer #2 · answered by jrnyofathsndyrs 2 · 0⤊ 0⤋
42101000
4 0's... 2 1's... 1 2... 0 3's... 1 4... 0 each 5's, 6's & 7's
2006-11-14 17:25:02 · answer #3 · answered by Ed M 1 · 0⤊ 0⤋
how about 60000010
bummer - gotta put numbers of 1's
*sigh* back to the drawing board
Try
42101000
2006-11-14 17:24:34 · answer #4 · answered by Orinoco 7 · 0⤊ 0⤋
42101000. I just got it by trial and error.
2006-11-14 17:28:27 · answer #5 · answered by Amy F 5 · 0⤊ 0⤋
sorry thats scaring me
2006-11-14 17:23:24 · answer #6 · answered by mz.thang 4 · 0⤊ 0⤋
try 42101000
2006-11-14 17:36:17 · answer #7 · answered by jaysintq 1 · 0⤊ 0⤋
42101000
I think this is it.
2006-11-14 17:26:21 · answer #8 · answered by moonfreak♦ 5 · 0⤊ 0⤋