I need this ASAP :)
2006-11-14 08:50:30 · 8 answers · asked by rebekahstadler 1 in Science & Mathematics ➔ Mathematics
11(p-3) = 5(p+3) Distrubute the 5 and 11
11p-33=5p+15 Subtract 5p and add 33 to both sides
6p=48 Divid both sides by 6
p=8
2006-11-14 08:55:37 · answer #1 · answered by futureastronaut1 3 · 0⤊ 0⤋
8
2006-11-14 16:54:45 · answer #2 · answered by Jim V 2 · 0⤊ 0⤋
11(p-3) = 5(p+3)
11p-33=5p+15
6p=48
p=8
2006-11-14 17:31:01 · answer #3 · answered by yupchagee 7 · 0⤊ 0⤋
11(p-3)=5(p+3)
11p-33=5p+15
-5p -5p
6p-33=15
+33 +33
6p=48
48/6
p=8
2006-11-14 17:15:36 · answer #4 · answered by chocolate~bunny 3 · 0⤊ 0⤋
11p - 33 = 5p + 15
6p = 48
p = 8
That's the work. So yeah, p is 8. I don't know about P though.
2006-11-14 16:55:00 · answer #5 · answered by Anonymous · 0⤊ 0⤋
11p - 33 = 5p + 15: 6p = 48: p = 8.
2006-11-14 16:55:07 · answer #6 · answered by Amy F 5 · 0⤊ 0⤋
11p-33=5p+15
6p=48
p=8
2006-11-14 16:55:37 · answer #7 · answered by Anonymous · 0⤊ 0⤋
It takes longer to post it than to solve it.
2006-11-14 16:53:59 · answer #8 · answered by modulo_function 7 · 0⤊ 0⤋