math question 2?

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Make up a polynomial that has the following characteristics: crosses the x-axis at -1, 4 and touches (but bounces back off) the x-axis at -3 and 6.

2006-11-14 07:56:59 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

Use single roots for -1 and 4, and double roots for -3 and 6. That is, just take the product (x + 1)(x - 4)*(x + 3)^2*(x - 6)^2.

2006-11-14 07:59:56 · answer #1 · answered by DavidK93 7 · 0⤊ 0⤋

f(x)=(x+1)(x-4)(x +3)^2 (x-6)^2
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2006-11-14 08:04:55 · answer #2 · answered by Anonymous · 0⤊ 0⤋