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Find the interval of convergence of the series:
http://img.villagephotos.com/p/2006-10/1221148/11.8.6.JPG

I started by using the ratio test, but reached a dead end:
http://img.villagephotos.com/p/2006-10/1221148/11.8.6.2.JPG

I know after the ratio test I must find the limit, and then evaluate endpoints for convergence/divergence. But I am stuck with how to find the limit as n --> ∞ of |x| lim (1/n+1)(n+n+1)^n.
Do I have to use L'Hopital's Rule since I get (∞/∞)^∞? Or does the limit = 0 because of 1/n+1? Or is it neither? I am totally confused and lost o_O.

We have an exam Friday, and having good work on HW problems will help for studying.

Thank you for your time and help! =)

2006-11-14 07:40:18 · 3 answers · asked by PuzzledStudent 2 in Science & Mathematics Mathematics

3 answers

the answer is 0

u know, lim 1/(n+1) = 0
n -> ∞

and, lim (n/n+1)^n = 1
n -> ∞

so: lim (1/n+1)(n/n+1)^n = lim (1/n+1) * lim(n/n+1)^n = 0 * 1 = 0
n -> ∞ n -> ∞ n -> ∞

2006-11-14 09:26:01 · answer #1 · answered by farbod f 2 · 0 0

Maybe something easier.

The series for exp(x) is similar but doesn't have the alternating sign and has a denominator that n! rather than n^n

since n^n >= n! (only equal for n=1) you can compare since each term in your series is smaller than that of exp x. Mayber to handle the alternating sign....no good idea on that.

2006-11-14 15:59:01 · answer #2 · answered by modulo_function 7 · 0 0

yes, take it to the hospital

2006-11-14 16:51:41 · answer #3 · answered by Jeff K 2 · 0 0

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