Physics help?

Question

An elevator starts from rest with a constant upward acceleration. It moves 2.0 meters in the first .60 seconds (that's a decimal in front of the 6, in case it's difficult to see). A passenger in the elevator is holding a 3.0-kg package by a vertical string. What is the tension in the string during the accelerating process?


I'm in a basic high school physics class, and i'm having some dificulty. Can you help? Be as detailed as possible please.

Answer 1

Start by considering all of the forces on the package:

Gravity: m*g
and the upward force of the acceleration, a, of the elevator
F=m*a

and the string holding the mass, which is the tension.
Since the mass is accelerating upward, then sum the downward forces to find the tension:

T=m*(g+a)
since we know the distance traveled and the time is with constant acceleration, then
d=1/2*a*t*t
or
a=2*d/(t*t)

So
T=m*(g+(2*d/(t*t))

plug in the numbers:
T=3*(9.8+(2*2/(.6*.6))
T=62.7N

j

Answer 2

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