A wire is first bent into the shape of an equilateral triangle with side 16cm . The wire is then bent into the shape of a rectangle with a length13cm. What is the width of the rectangle?
2006-11-14 07:00:16 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
16*3 = 48
So the wire is 48 cm long
48 - (13 *2) = 22
So each side is 11 cm
2006-11-14 07:02:15 · answer #1 · answered by leaptad 6 · 0⤊ 0⤋
First you have to figure out how much wire you have. The triangle has three sides which are all 16 cm, so the total length of wire is 3*16 or 48 cm. Now, you've got a rectangle with two sides known to be 13 cm long. The total length of wire used on these sides is 26 cm, leaving 22 cm for the other two sides. Therefore, they are 11 cm long.
2006-11-14 07:03:54 · answer #2 · answered by Amy F 5 · 0⤊ 0⤋
16 x3 = 48
48-13-13=22 which is the sum of the remaining two sides (or the width)
22 divided by 2 is 11
The answer is 11
2006-11-14 07:03:32 · answer #3 · answered by ssssss 4 · 0⤊ 0⤋
equilater triangle with side 16 cm perimeter is 16*3=48cm
rectangle will have the same perimeter
48=2l+2w
l=13
48=2*13+2w=26+2w
22=2w
w=11cm
2006-11-14 07:47:31 · answer #4 · answered by yupchagee 7 · 0⤊ 0⤋