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64y^2k^11/72k^3y^5

How to solve?

2006-11-14 05:52:13 · 2 answers · asked by Me 6 in Science & Mathematics Mathematics

also
(8x^7/7n) (56n/24x)

2006-11-14 05:57:11 · update #1

64y^2k^11/72k^3y^5
re typed

2006-11-14 06:02:10 · update #2

2 answers

8k^8/9y^3

1) Reduce 64/72 => Divide both sides by 8 => 8/9
2) Reduce y^2/y^5 => (2-5 = -3) => 1/y^3
3) Reduce k^11/k^3 => (11-3 = 8) => y^8

Combine all 3 => 8k^8/9y^3

2006-11-14 06:03:23 · answer #1 · answered by tedhyu 5 · 2 0

Could you re-type it in please. Some characters didn't come through.

2006-11-14 13:55:52 · answer #2 · answered by Teacher 4 · 0 0

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