Metallic molybdenum can be produced from the mineral molybdenite, MoS2. The mineral is first oxidized in air to molybdenum trioxide and sulfur dioxide. Molybdenum trioxide is then reduced to metallic molybdenum using hydrogen gas. The balanced equations are given below.
MoS2(s) + 7/2 O2(g) MoO3(s) + 2 SO2(g)
MoO3(s) + 3 H2(g) Mo(s) + 3 H2O(s)
Calculate the volumes of air and hydrogen gas at 21°C and 1.00 atm that are necessary to produce 1.00 103 kg of pure molybdenum from MoS2. Assume air contains 21% oxygen by volume and assume 100% yield for each reaction
what is the volume in L of air and Hydrogen?
please explain
2006-11-14 05:10:06 · 1 answers · asked by smile 1 in Science & Mathematics ➔ Chemistry
1. Work out the moles of pure Mo.
2. Multiply by 3 to get the moles of hydrogen.
3. Use V = nRT/p to calculate the volume of hydrogen.
4. Going back to the moles of Mo, multiply by 7/2 to get the moles of oxygen, and do a similar calculation to get the volume of pure oxygen.
5. Multiply the volume of oxygen by 100/21 to get the volume of air.
2006-11-14 05:21:17 · answer #1 · answered by Gervald F 7 · 0⤊ 0⤋