2006-11-14 05:08:05 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
You've got me... By definition they would have to be positive integers. So the absolute value of -y, would just be y...
If they are all prime, how can you represent z as the product of two other primes? That contradicts your assertion that they are all primes.
The only way to make this work is to allow 1 to be considered a 'prime' number, but with current definitions of prime, this is not the case, nor can 0 be considered prime...
Or if these are supposed to be the difference of factorials, there's another problem. Every factorial of a prime (2! or above), will have 2 as a factor. When you subtract two even numbers, the result is always even. So the only way be if x! and y! were within 2 of each other. Using the smallest primes possible (3! and 2!) you have 6 - 2 = 4, which is not 2.
Please explain what I'm missing...
2006-11-14 05:11:25 · answer #1 · answered by Puzzling 7 · 0⤊ 0⤋
Do you mean
z = x! - y! (ie. the difference between the two factorials)?
2006-11-14 13:18:07 · answer #2 · answered by modulo_function 7 · 0⤊ 0⤋