5x^4 -2x^2-(-x^4 -x^2)?

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5x^4 -2x^2-(-x^4 -x^2)?

2006-11-14 04:48:35 · 4 answers · asked by wanda_brown62 1 in Science & Mathematics ➔ Mathematics

4 answers

= 5x^4 - 2x^2 + x^4 +x^2
= 6x^4-x^2

2006-11-14 04:51:09 · answer #1 · answered by Anonymous · 0⤊ 0⤋

5x^4 -2x^2-(-x^4 -x^2)
=5x^4 -2x^+x^4+x^2
=6x^4 -x^2
=x^2(6x^2-1)
=x^2[(sq.root6)x-1] [(sq.root6)x+1]

2006-11-14 04:52:58 · answer #2 · answered by Dupinder jeet kaur k 2 · 0⤊ 0⤋

5x^4 -2x^2-(-x^4 -x^2)
5x^4+x^4-2x^2+x^2
6x^4-x^2
x^2(6x^2-1)
x^2(â6 x+1)(â6 x-1)

2006-11-14 04:53:51 · answer #3 · answered by yupchagee 7 · 0⤊ 0⤋

5x^4 -2x^2-(-x^4 -x^2)
= 5x^4 -2x^2+x^4+x^2
=6x^4-x^2
=(6x^2-1)x^2
x^2=0
x =0
6x^2-1=0
6x^2=1
x^2=1/6
x=+/-square root of (1/6) = +/-(square root of 6)/6

2006-11-14 05:24:11 · answer #4 · answered by Anonymous · 0⤊ 0⤋