this is regarding complex numbers
(\|-1)^2=(\|-1)*(\|-1)
-1=(\|-1*-1)
-1=\|1
-1=+or-1
2006-11-14 04:25:34 · 7 answers · asked by kapai 1 in Science & Mathematics ➔ Mathematics
i is define as sqrt(-1)
therfore i*i=sqrt(-1)*sqrt(-1)= -1
2006-11-14 04:30:45 · answer #1 · answered by Broden 4 · 0⤊ 0⤋
i ask you what is the answer of (x^2)^1/2
it is x not +-x
you are making a grevious mistake
for eg : 4^(1/2)=2 not +-2
((-1)*(-1))(1/2)= -1
therefore you are misunderstanding it
but make it clear 1^(1/2)=1 not +-1
2006-11-17 07:17:18 · answer #2 · answered by sidharth 2 · 0⤊ 0⤋
since by definition â-1=i then i^2 must=-1
I not sure your question.
is it that â-1=+/-i ?
while this is true, it doesn't change the answer.
just as (-2)^2=2^2=4; (-i)^2=i^2=-1
2006-11-14 12:57:56 · answer #3 · answered by yupchagee 7 · 0⤊ 0⤋
you r wrong in 2nd step as
-a^1/2*-b^1/2 = -(ab)^1/2
2006-11-14 13:57:05 · answer #4 · answered by Sam 1 · 0⤊ 0⤋
its simple
just that you cant combine square root of two negative numbers
2006-11-15 06:10:13 · answer #5 · answered by mit 1 · 0⤊ 0⤋
(\|-1)*(\|-1)=(\|-1*-1)
this is a wrong step
u cannot combine sq.root of
two negative terms
2006-11-14 12:29:58 · answer #6 · answered by Dupinder jeet kaur k 2 · 0⤊ 1⤋
You have it backwards:
(+i)² = -1
(-i)² = -1
sqrt(-1) = ± i
2006-11-14 12:30:07 · answer #7 · answered by Puzzling 7 · 0⤊ 1⤋