(1) 4x+3y= 19
(2) 2x+5y=3 multiply by 2
(2a) 4x+10y=6 Subtract (1) from (2a)
(1) 4x+3y= 19
(3) 7y=-13 divide by 7
y=-13/7
substitute into (1)
4x-3*13/7=19
4x-39/7=19 add 39/7
4x=(133+39)/7=172/7 divide by 4
x=43/7
solution is (43/7,-13/7)
check bt substituting into (2)
(2) 2x+5y=3
86/7-65/7=3
21/7=3
2006-11-14 05:09:40
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answer #1
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answered by yupchagee 7
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I assume the question is to solve for x and y (e.g. the point of intersection of the two lines).
I would double the bottom equation and subtract it from the first:
4x + 3y = 19
4x + 10y = 6
Subtracting the two equations:
-7y = 13
Divide by -7:
y = -13/7
y = -1 6/7
Finally substitute y back into one of the original equations:
2x + 5(-13/7) = 3
2x -65/7 = 3
2x = 3 + 65/7
2x = 21/7 + 65/7
2x = 86/7
x = 43/7
x = 6 1/7
As improper fractions:
x = 43/7
y = -13/7
As mixed fractions:
x = 6 1/7
y = -1 6/7
As a point of intersection, it would be:
(x,y) = (6 1/7, -1 6/7)
2006-11-14 12:13:26
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answer #2
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answered by Puzzling 7
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2x + 5y = 3
mens that
2x = 3-5y
x= (3-5y)/2
Now, we put that in the other eqaution
4x+3y=19
4(3-5y)/2 + 3y =19
6-10y + 3y=19
-7y =13
y=-13/7 (okay, so it is a nasty number, not a round integer)
that is -1.8571
Now, put this y value back in any of the original equation to solve for x:
2x + 5y=3
2x + 5(-13/7) = 3
2x -65/7 = 3
2x = 3+65/7
2x= 12.2857
x= 6.1428
2006-11-14 12:18:18
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answer #3
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answered by Vincent G 7
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4x+3y= 19
2x+5y=3
4x+3y= 19
-4x-10y=-6
-7y=13
y = -13/7
4x+3(-13/7)= 19
(28/7)x - (39/7) = (133/7)
28/7x = 172/7
x = 172/28
x = 43/7
2006-11-14 12:15:09
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answer #4
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answered by bourqueno77 4
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Multiply 2nd equation by 2 to get when you subtract only one variable
4x+3y=19
4x+10y=6
Subtracting equations 1 and 2,
-7y=13
y=-13/7
Substitute in 1st equation,
4x+3(-13/7)=19
Solve for x.
2006-11-14 12:12:30
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answer #5
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answered by Anonymous
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4x+3y=19
2x+5y=3
answer
4x+3y=19
4x+10y=6
---------
-6y=13
==>
y=-13/6
similarly
x=(19-9/5)/(4-6/5)=86/14=43/7;
so x=43/7,y= -13/6
2006-11-14 12:40:00
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answer #6
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answered by VADI R 1
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4x + 3y = 19-------x 1 (multiply by) eq. 1
2x +5y = 3-----------x 2 (multiply by) eq .2
4x + 3y = 19-------eq. 3
4x + 10y = 6---------eq. 4 Subtract eq. 3 from eq. 4 gives
-7y = 13 divide both sides by -7 gives
-7 -7
y = -13/7
Substitute y = -13/7 into eq.2 gives
2x +5(-13/7) = 3
2x + 0.844156 = 3
2x + 0.844156 - 0.844156 = 3 - 0.844156 (subtract 0.844156 both sides gives)
2x = 2.155844 divide both sides by 2 gives
x = 1.077922
I was doing this mentally use your calculator to find real answers.
2006-11-14 13:05:37
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answer #7
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answered by Anonymous
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given
4x+3y = 19 ....(1)
2x+5y = 3 ....(2)
x ing eq(1) by 2eq(2) by 4
(1)x2... 8x+ 6y = 38 .....(3)
(2)x4....8x+20y = 12 .....(4)
(3) - (4) ..
-14y= 26
y= -26/14
= -13/7
sub. the value of y in eq..(1)
4x+3*(-13/7)=19
x = (19+ 3*(13/7))/4
= 43/7
x=43/7
and y=-13/7
2006-11-14 13:16:15
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answer #8
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answered by george t 2
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I am a visitor math teacher from Venezuela
Y = 13/2
X= -59/4
My website is www.elprofesorcesar.tk
2006-11-14 12:19:32
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answer #9
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answered by cesar2356 3
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2x=3-5y
x=(3-5y)/2
6-10y+3y=19
7y= -13
y= -13/7
x=(3+65/7)/2
x=86/14 = 43/7
2006-11-14 12:18:55
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answer #10
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answered by carbonkid22 2
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