In root of -1*root of -1 is said to be-1 but root of-1*-1=root of 1 =1 or-1 then, why is (root of -1)^2 not -1

Question

MY QUESTION IS WITH RESPECT TO IMAGINARY NUMBERS OR COMPLEX NUMBERS IN MATHEMATICS

Answer 1

Who said sqrt(-1)² isn't -1?

sqrt(-1) = i
sqrt(-1)² = i²
sqrt(-1)² = -1

Answer 2

i^2 IS equal to -1

("i" is the way to write root of -1, by the way)

Answer 3

sqrt(-1) is called the imaginary number or i

i=i
i^2=-1
i^3=-i
i^4=1
i^5=i
i^6=-1

and keeps on repeating

i^2 should be equal to -1, similary like i^6

Typing "what is i squared" on google gives the answer "i squared = -1"

Answer 4

√-1=i by definition. (-1)^2=+1; i^2=-1
(√-1)^2 is -1
√-1=i; i^2=-1

Answer 5

because any negative number multiplied by itself is positive in the real number system