how do you determine the acceleration of a block that weighs 20kg down a ramp at a 15 degree angle. I need to know the equation to use for this. thanks!
2006-11-14 04:03:38 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Frictionless ramp
2006-11-14 04:09:55 · update #1
someone answered mg (sin15) that comes out to be newtons. That is 51.7n. that isnt the acceleration is it? its in newtons. HELP
2006-11-14 04:14:58 · update #2
once u figure out the acceleration how do u determine how long it will take it to travel 30 meters?
2006-11-14 04:24:05 · update #3
the mg*sin(15) was the force acting on the body in the direction along the ramp. now the acceleration is given by g*sin(15).
2006-11-14 04:21:55 · answer #1 · answered by Anonymous · 0⤊ 0⤋
The horizontal component of the force = mg.cos(15)
The vertical component= mg. sine(15)
So the force downard through the ramp=
=sqrt. m^2g^2.cos^2(15)+m^2g^2.sine^2(15)
=mg
Now, force=mass x acceleration
there for, acceleration=force/mass.
2006-11-14 12:37:41 · answer #2 · answered by Mathew C 5 · 0⤊ 2⤋
the component of gravity acting on the block along the slide is given by mg.sin 15...
threfore acceleration is mg(sin 15)
2006-11-14 12:11:51 · answer #3 · answered by indurti karthik 2 · 0⤊ 2⤋
you now the gravitational force is m*g and pointing downward:
the normal force will be -m*g*cos(15 degree)
the force force Fll parallel with the plane will be
Fll=mg*sin(15degree)
AND NOW WE CAN FIND all acc parallel with the plane:
Fll= m*aII=>
mg*sin*(15 degree)= m*a=>
a=g*sin*(15degree)
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2006-11-14 12:18:36 · answer #4 · answered by Broden 4 · 1⤊ 1⤋