if 3^-x=2, what does 3^2x equal?
2006-11-14 03:22:28 · 5 answers · asked by veryintrigued 2 in Science & Mathematics ➔ Mathematics
3^-x=2
-x ln3=ln2
-x=ln2/ln3
2x=-2ln2/ln3=-1.2618595071429148741990542286855
3^-1.2618595071429148741990542286855=.25
2006-11-14 05:16:21 · answer #1 · answered by yupchagee 7 · 17⤊ 3⤋
1/4
3^x = 1/2
3^x * 3^x = 3^2x = 1/2 * 1/2 = 1/4
2006-11-14 11:26:06 · answer #2 · answered by Dr. J. 6 · 1⤊ 0⤋
given that 3^-x=2
now 3^2x can be written as 1/3^-2x
now, since 3^-x=2, 3^-2x = 2*2 = 4
so, 3^2x = 1/4 or 0.25
2006-11-14 11:26:53 · answer #3 · answered by sameer 2 · 0⤊ 0⤋
3^-x=2
3^2x=1/3^-2x
=1/[(3^-x)^2]
=1/[2^2]
=1/4
2006-11-14 11:28:17 · answer #4 · answered by grandpa 4 · 0⤊ 0⤋
go to the logs
-x *log 3 =log2 x = - log2/log 3 = -0.63
and 3^-1.26 = 0.25
2006-11-14 11:29:36 · answer #5 · answered by maussy 7 · 0⤊ 0⤋