2006-11-14 03:20:19 · 9 answers · asked by BOO! 2 in Sports ➔ Football (American)
Zero. The first thing that needs to be pointed out is that a division winner automatically gets a playoff berth. The second thing is that everyone in the division plays everyone else twice. If all of those games inside the division ends in a tie, then its possible for everyone in the division ( if they all lose all of their games outside of the division ) to end the season with Zero wins, Ten losses, and Six ties ! From there we go through the N.F.L.'s tie-breaking system. For ties within a division, it will probably be broken up on level 6- Strength Of Schedule. The team with the toughest schedule will go to the playoffs. WITHOUT A WIN !!
2006-11-14 03:40:04 · answer #1 · answered by Count Acumen 5 · 2⤊ 0⤋
Here's a description:
Falsond go 1-15
Buccaners go 1-15
Panthers go 1-15
Saints go 2-14.
The Saints would go to the playoffs be cause they won they're division, it possible that if eveyone, except one, went 0-16, the other team wins one, they go. They division winners go to the playoffs, (Division, AFC East: Jets, Patriots, Bills, Dolphins) And the winner of the other seven go to the playoffs. Then, two teams that didn't win they're divisions, but had good records (I.e. Saints go 13-3, Panthers go 11-5) still good enough to go. But only the best two teams, they go as "Wildcards" and play the first week of the playoffs. No three teams can go to the playoffs from the same division (The problem with the AFC West right now, Bronchos are 6-2, Chargers are 7-2, Cheifs are 5-3, Guess who won't go?). I know this is a bit more then what you asked for, but explaining a few other things, like who the system works.
2006-11-14 13:04:18 · answer #2 · answered by Anonymous · 0⤊ 1⤋
8
2006-11-14 11:41:58 · answer #3 · answered by Anonymous · 0⤊ 2⤋
Three.
You play six inter-division games. If you beat each of your opponents once, and they each beat you once, and they beat each other once, each team will be 3-3 in the division. If each team in the division then loses all of their nondivision games, then each team will be 3-13. After that, since each team has identical division records and each team has beaten each other team once, it's up to strength-of-schedule tiebreakers, strength-of-lost-game tiebreakers (how good were the teams that beat you), then points fielded tiebreakers, then points allowed.
So I guess if the stars come together, the absolute minimum number of wins for an NFL playoff team is three.
2006-11-14 11:29:24 · answer #4 · answered by Brian L 7 · 4⤊ 1⤋
hmm..seeing how is is theo. possible for all teams to go 8-8, I'd guess that would be it (and the people with the best division records would go...but that would still be confusing), since for a team to win less, that would mean some other teams would have to win more, and the more you lower 1 team, the more you raise another, and so they'd even out (and if you did it more, they'd be below .500 and the 'other' team would be over, so they wouldn't make it).
2006-11-14 11:24:51 · answer #5 · answered by Andy T 4 · 0⤊ 3⤋
0 all division games throughout the division would have to be ties. Then lose and the rest of the division losing all of the rest of their games. It would come down to a tie breaker but 1 team from the division would have to go.
2006-11-14 11:23:27 · answer #6 · answered by Colin L 5 · 1⤊ 2⤋
4.
each division as 4 teams. so if one team wins one game against each of their division rivals (3 wins), plus one more game against one of their division rivals (4 wins), they would have the best division record, and it is possible that all of the other teams in their division would have a worse record than 4-12.
2006-11-14 11:29:39 · answer #7 · answered by mesquitemachine 6 · 1⤊ 2⤋
8, but a lot depends on your division. 10 or more makes things better
2006-11-14 11:29:23 · answer #8 · answered by Anonymous · 0⤊ 3⤋
i would say 10 games have to be won to get in
2006-11-14 11:30:49 · answer #9 · answered by blaze67247 5 · 0⤊ 3⤋