a^2+a^3+2a^2
3a^2 + a^3
= a^2(3 + a)
Until here is finished.... but...
..If you want the results for a ...do:
a^2(3 + a) = 0
a^2 = 0, 3 + a = 0;
a= 0 and a = -3.
PS: You can'tt get 4a^7 because you have to separate the a's that have exponencial 2 from the one with exponencial 3 in order to sum them in the ecuation. You can only add the exponencials if they are multiplying like this for example:
a^3 * a^2 = a^3+2 = a^5
2006-11-14 03:25:11
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answer #1
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answered by †Alessandra† 6
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If you were multiplying a^2 * a^3 * 2a^2 you would add the powers and multiply what was in front i.e (1*1*2) a ^ (2+3+2) = 2a ^7
But you are adding them so the powers don't change and you add up the number of them. So you have 1 and 2 = 3 a^2 and only one a^3. So...
a^2 + a^3 + 2a^2
= 3a^2 + a^3
Then simplifying further by removing common factors:
= a^2(3 + a)
2006-11-14 05:44:11
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answer #2
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answered by Steve G 2
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a^2 + a^3 + 2a^2
a squareds are like other a squareds and are different from a cubeds.
You can "collect together" all the terms that are a squareds
1 a squared plus 2 a squareds = 3 a squareds
( We don't write the 1 in front of a single a squared, we just know that a squared means 1 a squared.)
The a cubed is different from the a squareds, so you cannot "amalgamate" it with them
so a^2 + a^3 + 2a^2
=3a^2 + a^3
Each of the terms (parts separeated by a plus or minus sign) can be divided by a^2
3a^2 + a^3
a squared divided into 3 a squared goes 3 times
(3 a^2 means 3 x a x a)
similarly a^3 means a x a x a
so a^2 divided into a^3 goes a times
3a^2 + a^3
=a^2(3 + a)
2006-11-14 06:02:35
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answer #3
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answered by rosie recipe 7
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Remember that you can't add terms with different indices.
So a^2 + a^3 + 2a^2 = 3a^2 + a^3
You could factorise this expression by taking out common factors of 3a^2 and a^3.
Hence: a^2(3 + a) However, simplify usually means remove brackets.
2006-11-14 04:33:00
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answer #4
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answered by Anonymous
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a^2(3+a)
You just can't add powers, hon, you have to add the integer in front of the variable! For example, think of a^2 and a^3 as completely different variables such as x and y! If you substitued a^2 with x and a^3 with y, your equation would become >>> x + y +2x , now you wouldn't add the x's and y's together would you? And remember a^3=a*a^2 or A times A squared. So first add your like variables:
(1+2)a^2 + a^3 = 3a^2 + a^3 and you can rewrite it as:
3a^2 + a*a^2. To simplify you can factor a^2 out of both to get:
a^2(3 + a)
2006-11-14 03:18:07
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answer #5
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answered by carrieinmich 3
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Because a*2 and a*3 are two different expressions, they can't simply be added together. However, the a*2 and 2a*2 both contain the same index (power) so they can be added together.
e.g. 1 mars bar + 1 juice = 1 mars bar + 1 juice
but 1 mars bar + 2 mars bars = 3 mars bars
answer (before factorising) = 3a^2 + a^3
If you want it fully factorised your answer would be a^2(3+a)
2006-11-14 08:06:53
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answer #6
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answered by PaulK24 1
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If your "*" means "to multiply", then
2a + 3a + 4a = 9a
If your "*" means "the power of", then collect same power together (i.e. a*2 and 2a*2), the answer is
a*3 + 3a*2 = a*2(a + 3)
Hope this helps :)
2006-11-14 03:20:20
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answer #7
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answered by chyrellos 2
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a^2+a^3+2a^2
= 3a^2+a^3
= a^2(3+a)
2006-11-14 11:40:43
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answer #8
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answered by Kemmy 6
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a^2+a^3+2a^2
=a^2+2a^2+a^3
=3a^2+a^3
=a^2(3+a)
2006-11-15 09:00:59
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answer #9
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answered by Anonymous
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a*2+a*3+2a*2
=a*2+2a*2+a*3
=3a*2+a*3
=a*2(3+a)
2006-11-14 03:20:56
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answer #10
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answered by grandpa 4
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