pls give the solution...?

Question

a teacher is 15 years older than her student. in 15 years, the ratio of their ages will be 3:2. find their present ages

Answer 1

It's an algebra problem.


2 * Teacher's Age = 3 * Student's Age

Since the Teacher's Age = Student's Age + 15
S will equal the student's age.
2(S+15) = 3S
Would be your equation.

Distribute:
2S + 30 = 3S

Subtract 2S from both sides and you get:
S = 30.

The student is 30 years old. Since the teacher is 15 years older then the student, the teacher is 45 years old.

Why are people getting 15 and 30? That's a 2:1 ration, not 3:2.

Answer 2

Lets say that the age of the teacher is x, and the age of the student is y.
The first premise says that the student y=x-15.
The second premise says that in 15 years, the ratio will be 3 to two.
In other words, x+15 = (3/2)(y+15).
So, replace y with x-15, and the equation is
x+15=(3/2)(x)
x=(3/2)x -15
x-(3/2)x=-15,
-(1/2)x=-15
x=30.
Therefore, the teacher is 30, and the student is 15. In 15 years, the teacher will be 45, and the student is 30 (45 is 3 times 15, and 30 is 2 times 15).

Answer 3

OK, the first step with a word problem is to try to get it into an equation. Let's call the teacher's age T and the student's S. We're told that T = S + 15 and that (T+15)/(S+15) = 3/2.

Substituting the first equation into the second, we get (T+15)/T = 3/2. Multiplying both sides by 2 gives (2T + 30)/T = 3. Multiplying both sides by T gives 2T + 30 = 3T. Subtracting 2T from each side gives 30 = T. The teacher is 30.

Going back to the first equation, we see that T = S + 15, so S = T - 15, so the student is 15.

Finally, check your answer. The student is indeed 15 years younger than the teacher. In 15 years, they will be 30 and 45, which is a 3:2 ratio, so the answer checks out.

Answer 4

Let the age of the student be x =>
that the age of the Theacher y=x+15

about 15 years they will both be 15 years older

x(after 15 year)= x+15
y(after 15 years = y+15 = x+15+15 = x+30

now make the quotient
y(after 15 years )/x(after 15 year) = 3/2 =>

(x+30)/(x+15)=3/2 <=>
2x+60=3x+45<=>
x=15 => y= x+15= 15+15 =30
========================

Answer 5

Let the student's present age=x
Teacher's present age=x+15
Student's age after 15years=x+15
Teachers age after 15 years=x+30
[x+30]:[x+15]=3:2
2[x+30]=3[x+15]
2x+60=3x+45
x=15
Student's present age=15
Teachers present age=30
verify
45:30=3:2
ok

Answer 6

15 and 30

Answer 7

let student age be x
the teacher age x+15
after 15 yrs
age of student=x+15
age of teacher=x+30
x+30/ x+15 =3/2
2x+60=3x+45
x=15
x+15=30

Answer 8

x-y = 15
2x+30 = 3y+45

x = 15+y
30+2y+30-3y-45=0

x= 30 - teacher
y= 15 - student