ba-dum-pssh.
2006-11-13 21:35:15 · 10 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
I guess my sense of humor is too childish.
"ba-dum-pssh" the sound of percussion after telling a real zinger.
2006-11-15 03:30:02 · update #1
69
2006-11-13 21:41:23 · answer #1 · answered by Anonymous · 1⤊ 0⤋
integral of 2xdx is x^2.
Within the limits of 10 and 13, substitute x as 13 and 10 then subtract both. Thus,
13^2 - 10^ 2 = 169 - 100
= 69
2006-11-13 21:47:30 · answer #2 · answered by ludacrusher 4 · 4⤊ 0⤋
Integral of 2x dx = x^2
From x = 10 to x = 13,
the area is 13^2 - 10^2,
= 169 - 100
= 69
2006-11-13 21:50:13 · answer #3 · answered by falzoon 7 · 0⤊ 0⤋
The integral of 2x is x^2+c and putting the limits we get
13*13-10*10=69
2006-11-14 01:12:21 · answer #4 · answered by Napster 2 · 0⤊ 0⤋
Int 2x dx
=x^2
Inserting the limits
169-100
=69
2006-11-13 23:36:30 · answer #5 · answered by openpsychy 6 · 0⤊ 0⤋
Find the primitive of 2x, i.e. what do I have to differentiate to get 2x?
The answer obviously is x^2. (General rule for primitive of x^n is (x^(n+1))/(n+1) provided n is not -1)
Then you sub each of the boundary values (10 and 13) in this primitive and subtract. i.e. your answer is
13^2 - 10^2
Strictly speaking, the primitive of 2x is x^2 + C, where C is some arbitrary constant, because the derivative of a constant is zero. However, when you're going to substitute and subtract there's no point in including C, because
(13^2 + C -(10^2 + C)) is still 13^2 - 10^2.
2006-11-13 21:48:18 · answer #6 · answered by Hy 7 · 0⤊ 0⤋
Int(2x) = x^2 {13, 10}
13^2 - 10^2 = 69
2006-11-13 23:35:11 · answer #7 · answered by Dr. J. 6 · 0⤊ 0⤋
69
2006-11-14 00:16:47 · answer #8 · answered by Vaibhav cool 1 · 0⤊ 0⤋
2xdx
2017-01-13 10:41:49 · answer #9 · answered by wexler 4 · 0⤊ 0⤋
=2(X^2)|10,13=2*81=162
2006-11-13 22:49:51 · answer #10 · answered by Freddie 2 · 0⤊ 4⤋