log^2 3 - 3 log 10 + 2 log 10
2006-11-13 21:31:10 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
find out log3 and square it then find value of log10 and......
= (log3)^2 - log10(3) + log10(2) = (log3)^2 - 5(log10)
=(0.4771213)^2 - 3 + 2 [as log10=1]
= -0.77235526508631 (answer)
2006-11-13 21:49:09 · answer #1 · answered by Anonymous · 0⤊ 0⤋
This isn't an equation, so you don't "solve" it. I expect you were asked to simplify it or evaluate it. I don't understand what the first term is meant to be: Is it (log3)^2 or did you mis-type it:? I'm going to assume you meant log2^3, which is equal to
3 log 2.
But I'll use the reverse of that rule, and write the expression as
log 2^3 - log 10^3 + log 10^2, then use the rules
log a + log b = log ab
log a - log b = log (a/b) to get
log(2^3 * 10^2/10^3)
= log 0.8
2006-11-14 05:54:15 · answer #2 · answered by Hy 7 · 0⤊ 0⤋
as we know log10=1
therefore, log^2 3-3+2=log^2 3-1
which can be written as
(log3-1)(log3+1)
now put value and evaluate it.
2006-11-14 09:15:04 · answer #3 · answered by Napster 2 · 0⤊ 0⤋
Find log(3) and square it. Then subtract log(10)
(-3log(10) + 2log(10) = -1log(10))
2006-11-14 05:56:12 · answer #4 · answered by Helmut 7 · 0⤊ 0⤋
log^23-3lg10+2lg10
=[.4771]^2-3*1+2*1
=.2276-3+2
=.7724
2006-11-14 08:02:13 · answer #5 · answered by openpsychy 6 · 0⤊ 0⤋