A girl decides to become a cowgirl and is practising her lasso moves. She swings her lasso over her head at a radius of 1m with a centripetal acceleration of 16 m/s^2. What is the tangential speed, frequency and period of her lasso?
I've been trying to figure out how to do this but to no avail. Any step by step help would be greatly appreciated and rewarded points.
2006-11-13 20:57:11 · 1 answers · asked by Anonymous in Science & Mathematics ➔ Physics
meant to say question in the title.
2006-11-13 21:08:22 · update #1
The centripetal acceleration of circular motion a = w*2*r, where w is the angular velocity. Since you know a = 16m/sec^2, and r = 1m, then w=√[a/r] The tangential speed = r*w. In these formulas w is in radians/sec. The frequency is in cycles (rotations) per second, one rotation = 2π radians. The period is one over the frequency.
2006-11-13 21:11:14 · answer #1 · answered by gp4rts 7 · 0⤊ 0⤋