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A sled slides along a horizontal surface on which the coefficient of kinetic friction is 0.25. Its velocity at point A is 8m/s and at point B is 5m/s.

in seconds

2006-11-13 19:27:58 · 1 answers · asked by iknowu2jan 3 in Science & Mathematics Physics

1 answers

F(t-t0) = m(v - v0)
F = 0.25W = 0.25mg
0.25*9.80662*t = 8 m/s - 5 m/s
t = 3/(0.25*9.80662) s
t = 1.2237 s

2006-11-13 19:41:51 · answer #1 · answered by Helmut 7 · 2 0

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