Please solve this Quadratic equation?

Question

2(x + 1)(x - 3) = 24 - 11x
Anyone? : )

Answer 1

2(x'-2x-3)=24-11x
2x'-4x-6=24-11x
2x+7'x-30=0
(2x-5)(x+6)=0
2x=5 or x=6
x=5/2 or x=-6

x'=x*x

Answer 2

2(x + 1)(x - 3) = 24 - 11x

To solve this equation, we need to first of all put it in the general format of quadratic equations which is:

ax^2 + bx + C = 0

To do this, we start by expanding the brackets

we handle the (x + 1)(x - 3) bit first we have:
x^2 - 2x - 3

2(x^2 - 2x - 3) = 24 - 11x
expanding the brackets we have
2x^2 - 4x - 6 = 24 - 11x

Move everything to the left hand side of the equation and equate to zero:

2x^2 - 4x + 11x - 6 - 24 = 0
2x^2 + 7x - 30 = 0
2x^2+12x - 5x - 30 = 0
2x(x + 6) - 5(x+6) = 0
(2x - 5)(x + 6) = 0

Either 2x - 5 = 0 or x + 6 = 0
So 2x = 5 or x = -6
x = 5/2 or -6

Answer 3

2(x + 1)(x - 3) = 24 - 11x
(2x + 2)(x - 3) = 24 - 11x
2x² - 6x + 2x - 6 = 24 - 11x
2x² - 6x + 2x + 11x - 6 - 24 = 0
2x² + 7x - 30 = 0
(2x - 5)(x + 6) = 0
x = 5/2, x = -6

Answer 4

multiplying and arranging:
2x^2+7x-30 = 0
2x^2+12x-5x-30=0
2x(x+6)-5(x+6) = 0
(2x-5)(x+6) = 0
x=5/2 or x= -6