we have 13, five-hundred pound men streaking down the road at 37 miles per hour, how long will it take these large men to streak 15 miles, if these men stop for 2 minutes because they see a hot dog stand and decide to eat, then carry on at the same speed for the remainder of the distance???
2006-11-13 17:42:19 · 3 answers · asked by bigschwinger 2 in Science & Mathematics ➔ Physics
The fact that there are 13 of them and they weigh 500 lbs each is irrelevant to this problem. The answer is simply to use the equation:
Distance = Speed * Time
Thus, if thhey are traveling at 37 mph for 15 miles, the time required is:
Time = Distance / Speed
T = 15 mi / 37 mph = (15/37) h * 60 min/hr
T = 24.32 min.
If they stop for two minutes to eat, then carry on at the same speed, then two minutes is added to their required time (assuming that their eating time is independant from one anaother):
T = 26.32 min
Good luck! :)
2006-11-13 17:52:21 · answer #1 · answered by Rob S 3 · 1⤊ 0⤋
Please do not post pictures!!!
t = d/v + t0 = 15 miles/37 mph *60 min/hr + 2 min = 26.3 minutes
2006-11-13 17:56:56 · answer #2 · answered by d/dx+d/dy+d/dz 6 · 0⤊ 1⤋
I'd say about 11.26 minutes.
2006-11-13 18:14:15 · answer #3 · answered by tcdj4l 3 · 0⤊ 1⤋