Can someone please explain to me how the arc csc of sqrt 2 is 4pi/3.?

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2006-11-13 16:36:22 · 4 answers · asked by Brian 2 in Science & Mathematics ➔ Mathematics

By "csc" I mean cosecant and "sqrt" meant squareroot.

2006-11-13 16:41:54 · update #1

sin(3pi/4)= 1/sqrt(2) = sin(pi/4)
csc(3pi/4)=csc(pi/4) = sqrt(2)
acsc(sqrt(2))=pi/4

4pi/3 just doesn't work.

2006-11-13 16:48:39 · answer #1 · answered by Anonymous · 0⤊ 0⤋

For any cosecan value it will fall between 0 to 1 only and hence there is no chance for the value to become squareroot of 2

2006-11-14 01:14:43 · answer #2 · answered by rajr59 2 · 0⤊ 0⤋

Sorry, but arc csc(â2) = Ï/4.
sin(Ï/4) = (â2)/2
csc(Ï/4) = 1/sin(Ï/4) = 2/â2 = â2

2006-11-14 01:04:39 · answer #3 · answered by Helmut 7 · 0⤊ 0⤋

wats csc here
ur Q is not clr

2006-11-14 00:40:12 · answer #4 · answered by . 3 · 0⤊ 0⤋