please help with physics!!?

Question

The displacement vector for a 15.0 second interval of a jet airplane's flight is (2450, −2430) m. (a) What is the magnitude of the average velocity? (b) At what angle, measured from the positive x axis, did the airplane fly during this time interval?

Answer 1

This is easy. The displacement is sqrt(2450^2 + 2430^2) = 10 sqrt(245^2 + 243^2) = 3451 m, so the average velocity is 230 m/s. (You had to divide by 15.)

For the angle, tan x = -243/245 = -0.99184

The angle is -44 degrees, 46 minutes

Answer 2

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