Calculate the speed acquired and the distance covered in 4 sec from rest
2006-11-13 14:54:14 · 3 answers · asked by theedrunkenclam 1 in Science & Mathematics ➔ Physics
Did you forget the equations for velocity as a function of time and distance as a function of time, given a acceleration?
2006-11-13 14:56:57 · answer #1 · answered by arbiter007 6 · 0⤊ 0⤋
the gap traveled whilst accelerating = 20 x 10 / 2 = one hundred whilst consistent = 20 x 10 = 200 whilst decelerating = same as accel complete = one hundred + 200 + one hundred = 4 hundred m this in touch one extensive velocity time graph.
2016-12-10 08:43:55 · answer #2 · answered by Anonymous · 0⤊ 0⤋
V=at --> 20m/s after 4 sec
X=Xnot+VnotT+1/2aT(squared)
X=32m
comon, this should be an easy question for you. Its already november. Im a freshman in high school and we did this in early september.
2006-11-13 15:28:16 · answer #3 · answered by Anonymous · 0⤊ 0⤋