Can anybody please help me on this question im stuck!?

Question

A wire is first bent into the shape of a rectangle with width 5cm and length 7cm. The wire is then bent into the shape of an equilateral triangle. What is the length of a side of the triangle?

Answer 1

The length of the wire must be (2x5)+(2x7)=24cm. So each side of the triangle must be 24/3=8cm. long.

Answer 2

First, you need to examine the perimeter of the rectangle. You know that P = 2*w + 2*L = 2*5 + 2*7 = 10 + 14 = 24 cm.

So, the wire must be 24 cm.

Now, you need to know the perimeter of an equilateral triangle. An equilateral triangle has all three sides equal. So, to figure out the length of one side, you divide 3 into the perimeter, which gives you 8 cm.

Answer 3

So the total length of the perimeter of the rectangle is 5+7+5+7 or 24, now divide that by the number of sides of an equilateral triangle (3) and you get 8 .... So each side of the triangel would have to be 8cm to be the same perimiter of the original rectangle.

Answer 4

perimeter of a rectangle is measured by doubling the length, the doubling the width and adding the values together. Therefore, 5(2)+(7)2=24. An equilateral triangle has three congruent sides. Therefore, 3x=24 and x=8. One side of the triangle is equal to 8 cm.

Answer 5

Length of wire = 5+5+7+7=24cm
Sides of equilateral triangle are all equal so each side must be 24/3 = 8cm

Answer 6

The main thing to realize is that the perimeter is the same for both the rectangle and the triangle because you're just changing the shape of the wire.

The perimeter of the rectangle is 2w + 2l.
The perimeter of the triangle is 3s (since all three sides are equal).

2w + 2l = 3s
2(5) + 2(7) = 3s
s = 8