A wire is first bent into the shape of a rectangle with width 9in and length 11in . The wire is then bent into the shape of a square. What is the length of a side of the square?
Please someone answer my question correctly!
I dont want to give out those 10 points just for nothing so please be true!
Cause i like true people!☺
2006-11-13 14:25:00 · 15 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Length of wire = 9in+9in+11in+11in
=40in
Length of Square = 40in divide by 4
= 10in
2006-11-13 14:27:42 · answer #1 · answered by A 150 Days Of Flood 4 · 1⤊ 0⤋
I'm not sure if I understand your question correctly, but..
With a rectangle of 9in width and 11in length, the perimeter of the rectangle is 40 in.
The same wire bent into a square would have the same perimeter, but with 10 in on each side.
2006-11-13 22:29:57 · answer #2 · answered by mmonkeyccup 2 · 0⤊ 0⤋
The perimeter of the rectangle is equivalent to that of the square so . . .
Rectangle Perimeter Formula:
P=2l+2w
Solution:
P=(2*11)+(2*9)
=(22)+(18)
=40
Square Perimeter Formula:
P=4s
Solution:
40=4s
40/4=s
10=s
FINAL ANSWER: The length of a side of the square is 10 inches.
2006-11-13 22:38:23 · answer #3 · answered by ixamint 1 · 0⤊ 0⤋
The perimeter of the rectangle is 9+9+11+11 in, or 40 in. The perimeter of a square is 4x, where x is the length of a side. Since the square is made from the same piece of wire as the rectangel, it will have the same perimeter. So:
4x=40
x=10
The length of a side of the square is 10 in.
2006-11-13 22:28:17 · answer #4 · answered by Pascal 7 · 0⤊ 0⤋
Find P, the perimeter of the rectangle. Now, a square has 4 equal length side, so S = P/4.
Perimeter of rect is 2 times length plus 2 time the width, right? Just draw a little sketch and walk around it. You know your width and length, so you can get P then S.
2006-11-13 22:31:25 · answer #5 · answered by modulo_function 7 · 0⤊ 0⤋
Hi. Take the length of the perimeter of the first rectangle (9+9+11+11) then divide that number by 4.
2006-11-13 22:27:54 · answer #6 · answered by Cirric 7 · 0⤊ 0⤋
10 inches.
9 + 9 + 11+ 11 = 40 so each side of the square has to be 10 if you have 40 inches of wire to work with.
2006-11-13 22:28:20 · answer #7 · answered by FabMom 4 · 0⤊ 0⤋
10....2 sides are 9 and 2 are 11. 9+9+11+11=40.....40/4=10
2006-11-13 22:38:13 · answer #8 · answered by travis121980 1 · 0⤊ 0⤋
11+9+11+9 = 40 inch wwire
4 eaual sides out of a 40 inch wire is 10 inches on each side...
come on, you could have done that one.
2006-11-13 22:32:35 · answer #9 · answered by Anonymous · 0⤊ 0⤋
length + width = 9 + 11 = 20
wire can be reshaped, keeping length + width still equal to 20
for a square length and width will be equal, so length and width would have to be 10 each.
(so area is now 100 whereas previously it was 99)
2006-11-13 23:07:02 · answer #10 · answered by paladin 1 · 0⤊ 0⤋