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1.A man standing on top of a building sees an automobile on a street below him.The angle of depression is 36 degrees 22. If eye is 550 ft. above the level of the automobile ,how far is the automobile from him?
2.In a right triangle, given a= 32.8 ft. and A=28° 30’ 15’’,solve for B and C
2006-11-13 13:54:47 · 3 answers · asked by hitman 1 in Science & Mathematics ➔ Mathematics
Draw the right triangles indicated. Remember that the angle of depression from top to bottom equals the angle of elevation from bottom to top, so write the 33 degrees 22 down at the bottom inside the triangle. Then see if you have adjacent leg, opposite leg, and/or hypotenuse; use sine if opp and hyp, cos if adj and hyp, tan if opp and adj.
2006-11-13 13:59:37 · answer #1 · answered by hayharbr 7 · 0⤊ 0⤋
Ouch you made my brain hurt gues I'm a litte rusty at trig. Problem two is real easy though. A + B + C = 180. Since Angle A is give and angle B is always 90 on a right triangle add 90 + 28.3015 subtract that total from 180 to find angle C.
Now for the problem that made my brain hurt.
Do the same thing for prob 1 to find the missing angle which is 53.78. Now multiply 550 * tan 36.22 to get side b or a depending on your perspective. Now use the the pathagorean theorem a^2 + b^2 = c^2 sqr of c^2 is side c.
should be 681.7xxxxx
2006-11-13 16:05:16 · answer #2 · answered by ikeman32 6 · 0⤊ 0⤋
ur way to lazy..also..this is really basic trig..u should have learned it during geomertry. I"m not even in trig and this is really easy.
2006-11-13 13:56:53 · answer #3 · answered by alex_ahn91 1 · 0⤊ 1⤋
On 2, use the law of cosines.
2006-11-13 13:56:53 · answer #4 · answered by Adriana 4 · 0⤊ 0⤋