A is a variable along with B and t but t is what I'm looking for
2006-11-13 13:50:52 · 5 answers · asked by Edward S 1 in Science & Mathematics ➔ Mathematics
A/B=e^(-t/5)
ln(A/B)=-t/5
-t=5ln(A/B)
t=-5ln(A/B)
2006-11-13 13:52:46 · answer #1 · answered by Greg G 5 · 0⤊ 0⤋
Divide both sides by B to get (A/B)= e^(-t/5)
The inverse of e to a power is ln (natural log) so do ln of both sides:
ln(A/B) = ln(e^-t/5) ; the ln and e cancel out to leave -t/5
Multiply both sides by -5 and get -5 ln (A/B) = t
2006-11-13 21:55:47 · answer #2 · answered by hayharbr 7 · 0⤊ 0⤋
Divide both sides by B and take LOGARITHM on Both Sides
ln ( A/B)=ln(e^(-t/5))
Right Hand Side is simmply -t/5
ln( A/B)= -t/5
FInd t now ?? easy right
2006-11-13 21:54:27 · answer #3 · answered by ? 1 · 0⤊ 0⤋
A
=Be^-t/5
lnA
=lnB-t/5
t/5
=lnB-lnA
=5lnB/A
t
=ln[B/A]^5
2006-11-14 07:49:34 · answer #4 · answered by openpsychy 6 · 0⤊ 0⤋
how nerdy i love it,, im baffled but i love it,,
2006-11-13 22:00:01 · answer #5 · answered by Ivy S 2 · 0⤊ 0⤋