A person of mass 75 kg stands at the center of a rotating merry-go-round platform of radius 2.9 m and moment o

Answer 1

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Answer 2

ok first of all...the answer above me doesnt artwork because how in the international might want to the kinetic potential be an similar if the angular % adjustments? ok that is a issue the worries conservation of angular momentum. because the angular momentum is conserved L_1=L_2. L=I*w because the guy is status contained in the middle of the merry flow round at the starting up, he has no effect on the momentum of the merry flow round so L_p=(500)*(2.0)=1000 (p stands for platform) because the momentum of the merry flow round formerly the guy walks is going to be an similar because the momentum after the guy walks, L_p=L_w (L_w is the momentum after the guy walks) So (I_p)*(w)=(I_p+I_w)*(w) or (500)*(2.0)=((500)+(a million/2)*(seventy 5)*(2.9))*(... remedy for w and look at were given your very last angular % a million.6427 For the kinetic energies... your formerly is going to be K_1=(a million/2)*(I_p)(w^2) or K_1=(a million/2)*(500)*(2.0^2) your after kinetic potential is going to be K_2=(a million/2)*(I_p+I_w)(w_f)^2 w_f is your very last angular % or (a million/2)*(500+((a million/2)*(seventy 5)*(2.9)))(a million.6427^2) desire this allows:)