Propane, C3H8(g) is used as a fuel in gas barbecues. It burns in oxygen to produce carbon dioxide and water vapour.
C3H8(g) + O2(g) à CO2 (g) + H2O (g)
a) Balance the equation for this reaction
b) How many moles of propane are needed to produce 6 mol of carbon dioxide?
2006-11-13 12:58:53 · 6 answers · asked by untilyoucamealong04 3 in Science & Mathematics ➔ Chemistry
OK. To balance the reaction, you need to end up with the same number of atoms of each kind on both sides of the arrow. Generally start with carbon, and then with hydrogen, and then finally balance the oxygen.
I think you'll end up with:
C3H8(g) + 5 O2(g) --> 3CO2(g) + 4 H2O(g)
The equation says that 1 mol of propane will produce 3 mol of carbon dioxide. So, in order to produce 6 moles of carbon dioxide, you will need 2 mols of propane.
2006-11-13 13:04:19 · answer #1 · answered by hcbiochem 7 · 0⤊ 0⤋
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2016-11-23 20:26:51 · answer #3 · answered by Anonymous · 0⤊ 0⤋
This is stoichiometry.
You are being given info about one thing but being asked for info about another.
A. C3H8(g) + 5 O2(g) --> 3CO2(g) + 4 H2O(g)
B. 2 moles Propane
2006-11-13 13:07:18 · answer #4 · answered by Chem_lover_Chris 2 · 0⤊ 0⤋
a) C3H8 + 5 O2 -----> 3 CO2 + 4 H2O
b) 6mols CO2 / 3mols CO2 per 1mol C3H8 = 2 mols of propane
2006-11-13 13:03:58 · answer #5 · answered by Kiri 4 · 0⤊ 0⤋
a) C3H8 + 5O2 ----> 3CO2 + 4H2O
b) pretty sure it's 2 mol C2H8
2006-11-13 13:15:27 · answer #6 · answered by Anonymous · 0⤊ 0⤋