so the problem is:
A rectangle's height is 3 less than twice its width. Perimeter is 66.
Width?
2006-11-13 12:56:23 · 7 answers · asked by emma 4 in Education & Reference ➔ Homework Help
never mind, i figured it out
it's (2x-3)+(2x-3)+x+x=66
6x-6=66
6x=72
x=12
2006-11-13 13:04:20 · update #1
sorry but 12 IS the right answer, not 18 or 11, but thanks for the help!
2006-11-13 13:05:25 · update #2
Let the width be x.Therefore height is 2x-3
Therefore its perimeter=2(x+2x-3)=6x-6
=>6x-6=66
=>6x=66+6=72
=>x=72/6=12 ans
2006-11-13 13:03:23 · answer #1 · answered by alpha 7 · 0⤊ 0⤋
I am pretty sure it is 11 because then if the width is x and then the height is 2x-3. Then you multiply both amounts by 2 to get amount of all sides which equals 6x-6=66(the perimeter) and then add 11 to both sides to get 6x=66 and divide both by 6 to get 11. And since we used x for width and x is 11, then ................x=11
2006-11-13 21:01:09 · answer #2 · answered by ostentatiousenigam 2 · 0⤊ 0⤋
A rectangle's length is 4 more than twice its width. ... that does not belong 66 333 99 111 88 also if you have 3 ... make the Missile path less steep near A and B and to keep the height ...
2006-11-13 21:01:52 · answer #3 · answered by x_x_andre_x_x 3 · 0⤊ 0⤋
H=height
W=width
W=H-3 The formular for width
2H+2W=66 (Perimeter is 2 heights plus 2 widths)
Then just substitute. Plug in the W.
2H+2(H-3)=66
2H+2H-6=66
4H=72
H=18
Then u go back and substitute plug in 18 for H in the formula for width.
W=18-3
Width=15
2006-11-13 21:00:52 · answer #4 · answered by I Like Hột Vịt Lộn! 2 · 0⤊ 0⤋
Perimeter = 2w + 2h
h=2w-3
p=66.
Plug things in. Hope that gets you started.
2006-11-13 20:58:55 · answer #5 · answered by Tony P 2 · 0⤊ 0⤋
2H + 2W = 66
2(W-3) + 2W = 66
2W - 6 + 2W = 66
4W - 6 = 66
4W = 72
W = 18
*****Check your math, in a step you added 2x + 2x and got 6x
2006-11-13 21:02:19 · answer #6 · answered by Film XPress 1 · 0⤊ 0⤋
calculator
2006-11-13 21:04:41 · answer #7 · answered by hi_hoppe 1 · 0⤊ 0⤋